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Early Solutions to the 2024 AP Precalculus Free Response

The innaugural AP Precalculus Exam is now complete, and we're here to offer our early attempt at solutions to the four free response questions. Luckily, we knew what questions were coming, since all the AP Precalc FRQs are based on task models that the College Board shared with us throughout this school year. True to their word, the College Board gave us four questions that reflected the four task models:


  • FRQ 1: Function Concepts

  • FRQ 2: Modeling a Non-periodic Context

  • FRQ 3: Modeling a Periodic Context

  • FRQ 4: Symbolic Manipulations


You can see this year’s AP Precalc questions here. Although the official scoring guidelines don’t release until the summer, here’s a first attempt at solutions. (Please be gentle if we have any errors!).


FRQ 1: Function Concepts

FRQ 2: Modeling a Non-periodic Context


FRQ 3: Modeling a Periodic Context

FRQ 4: Symbolic Manipulations


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7件のコメント


Patti Delmonte
Patti Delmonte
2 days ago

For 2Aii your natural log function G(t) should be 40 + 7.961ln(t+1) not ln(t). I assume this was just a typo (do you call it a typo if it is written?) because you used the function correctly in the next part.

いいね!

Sarah Carvellas
Sarah Carvellas
3 days ago

I have two questions. In 1, c, ii) do you think it is sufficient to say that f is not invertible because it is not one-to-one?

And in 4B, you don't actually have to simplify the logarithm that much, right? Like would it be full credit to say log (8x^5*2x^2/x^9) with no further work shown?

いいね!
Greg McGuire
Greg McGuire
3 days ago
返信先

No, I don't think that would be sufficient for 1,c,ii, since the question asks that it be "based on the definition of a function". That implies that you need to specifically tell how failing to be one-to-one means that the inverse would not meet the definition of a function.

The 3rd bullet in the directions for problem 4 requires that it be simplified.

いいね!

Matt Dodd
Matt Dodd
4 days ago

I'm getting a different answer for #3 part B, for the constant "c." I got 0, since there is no phase shift (function intersects midline on the y-axis). My function is h(t) = -9 sin (pi (t + 0)) + 9.


https://www.desmos.com/calculator/h5wecttubd


edit: I see that c = 2 (and -2) also works with an amplitude of -9 :-)

いいね!
Sarah Carvellas
Sarah Carvellas
3 days ago
返信先

Matt, I did it just like you did.

いいね!
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